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if you have a bag of chocolate candy, ten are red, 7 are brown, 12 are green, and 9 are blue, what is the probability of you picking a red candy given that you already picked a blue candy and have not replaced it?

  • math -

    10 + 7 + 12 + 8 = 37

    10/37 = 0.27 = 27%

  • math -

    10/37

  • math -

    10/37

  • math -

    the actual answer is 9/37

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