4gm NaOH are contained in 1deci litre of a solutio,calculate the mole fraction of NaOH?

To calculate the mole fraction of NaOH in a solution, you need to know the moles of NaOH and the total moles of all the components in the solution.

First, we need to convert the given mass of NaOH into moles. To do this, we need the molar mass of NaOH, which consists of one atom of sodium (Na) with a molar mass of 22.99 g/mol and one atom of oxygen (O) with a molar mass of 16.00 g/mol, along with one atom of hydrogen (H) with a molar mass of 1.01 g/mol. The molar mass of NaOH is:

(1 * 22.99 g/mol) + (1 * 16.00 g/mol) + (1 * 1.01 g/mol) = 39.01 g/mol

The moles of NaOH can be calculated by dividing the given mass (4 g) by the molar mass:

4 g / (39.01 g/mol) ≈ 0.1024 mol

Next, we need to calculate the total moles of all the components in the solution. Since the volume is given in deciliters (dL), we convert it to liters by dividing by 10:

1 dL / 10 ≈ 0.1 L

Now, we can assume the density of the solution to be the same as water, which is approximately 1 g/mL or 1 kg/L. Therefore, the mass of the solution is equal to the volume:

0.1 L * 1 kg/L = 0.1 kg

Now, we need to calculate the moles of water in the solution. The molar mass of water (H2O) is 18.02 g/mol. To convert the mass of water to moles:

0.1 kg / (18.02 g/mol) ≈ 5.55 mol

Finally, we can calculate the mole fraction of NaOH by dividing the moles of NaOH by the total moles of all components:

Mole fraction of NaOH = moles of NaOH / (moles of NaOH + moles of water)
Mole fraction of NaOH = 0.1024 mol / (0.1024 mol + 5.55 mol) ≈ 0.018

Therefore, the mole fraction of NaOH in the solution is approximately 0.018.