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What is the mole fraction of NaOH,when 4gm of NaOH contained in 1deci litre of solution?
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4gm NaOH are contained in 1deci litre of a solutio,calculate the mole fraction of NaOH?
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To calculate the mole fraction of NaOH in a solution, you need to know the moles of NaOH and the
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100g of water is added into 10.6M NaOH solution. The diluted NaOH then neutralized completely with H2SO4 . density of NaOH is
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100g of water is added into 10.6M NaOH solution. The diluted NaOH then neutralized completely with H2SO4 . density of NaOH is
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Adding 100-g HOH = 100-ml HOH into 10.6-M NaOH => 10.6 mole/Liter + 0.100L HOH => 10.6 mole
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im not sure how u solve these types of problems...
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pls can anybody check my answers
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Not for homework, just practice problems I'm having trouble with.
Knowing that one mole of KHP, C8H5O4K, reacts with one mole of
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Okay, I think i understand the second question. moles=MxV so... moles=(24.5ml)(0.10M NaOH) = 2.45
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What is the mole fraction of NaOH in an aqueous solution that contains 20.5% NaOH by mass?
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What is the mole fraction of NaOH in an aqueous solution that contains 33.4% NaOH by mass?
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