algebra 
posted by marko .
#21 can you help me solve this equation:
3x^2 (2x  2)
i keep getting: 6x ^2 6
#22 can you check this one:
(2x ^2) (6x^2)
i got 12x
#23 can you check this one:
(4m^2 + m 2) + (m^2  3m)
i got: 4m ^2 + 4m2
#25 can you check this one:
(3x^2 x 1) + (2x^2 + 2x 1)
i got: 6x ^2 +1x
#26 (2n^3)(2n)
i am stuck i got: 2n^3 *2n

for #26 i got: 4n^4

#22 i got 12 x ^4

#23 should be i got: 5m^2  2m 2

# 21
3 x ^ 2 ( 2 x  2 ) =
3 x ^ 2 * 2 x  3 x ^ 2 * 2 =
6 x ^ 3  6 x ^ 2 =
6 x ^ 2 ( x  1 )
# 22
( 2 x ^ 2 ) ( 6 x ^ 2 ) =
6 * 2 * x ^ 2 * x ^ 2 =
12 x ^ 4
# 23
( 4 m ^ 2 + m  2 ) + (  m ^ 2  3 m ) =
4 m ^ 2 + m  2  m ^ 2  3 m =
3 m ^ 2  2 m  2
# 25
( 3 x ^ 2  x  1 ) + ( 2 x ^ 2 + 2 x  1 ) =
3 x ^ 2 + 2 x ^ 2  x + 2 x  1  1 =
5 x ^ 2 + x  2
# 26
(  2 n ^ 3 )( 2 n ) =
 2 * 2 * n ^ 3 * n =
 4 n ^ 4 
bosnian
for #23
i got 5m ^2  2m  2
can you explain this one again 
( 4 m ^ 2 + m  2 ) + (  m ^ 2  3 m ) =
4 m ^ 2 + m  2 + (  m ^ 2 ) + (  3 m ) =
4 m ^ 2 + m  2  m ^ 2  3 m =
4 m ^ 2  m ^ 2 + m  3 m  2 =
3 m ^ 2  2 m  2
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