Make a solution of the following:
4ml of 0.5m cupric sulphate pentahydrate.
5ml of 250mm cupric
sulphate pentahydrate.
and
6ml of 125mm cupric sulphate pentahydrate.
What is the question?
To make the solution, you will need to calculate the amount of cupric sulfate pentahydrate needed for each of the given quantities.
1. For 4 mL of 0.5 M cupric sulfate pentahydrate:
0.5 M means 0.5 moles of CuSO4•5H2O per liter of solution. Therefore, to calculate the amount of cupric sulfate pentahydrate needed, use the formula:
moles = molarity × volume (in liters)
moles = 0.5 mol/L × 0.004 L (since 4 mL equals 0.004 L)
Calculate the moles of cupric sulfate pentahydrate for 4 mL, and then check the molar mass of CuSO4•5H2O to convert moles to grams. Finally, add the obtained amount of cupric sulfate pentahydrate to the solution.
2. For 5 mL of 250 mM (millimolar) cupric sulfate pentahydrate:
250 mM means 250 millimoles of CuSO4•5H2O per liter of solution. Similar to the previous calculation, use the formula:
moles = molarity × volume (in liters)
moles = 250 mmol/L × 0.005 L (since 5 mL equals 0.005 L)
Calculate the moles of cupric sulfate pentahydrate for 5 mL, and then convert moles to grams using the molar mass of CuSO4•5H2O. Add this amount of cupric sulfate pentahydrate to the solution.
3. For 6 mL of 125 mM cupric sulfate pentahydrate:
Follow the same steps as above using the molarity of 125 mM and volume of 0.006 L (6 mL equals 0.006 L).
By calculating the amount of cupric sulfate pentahydrate for each given quantity, you can create a solution containing these components. Please note that additional solvent may be required to achieve the desired final volume of the solution.