a stone of mass 50g is being rotated in a circle of r 50cm with a uniform speed of 2m\s. what is the acceleration of the stone
mv^2/r
To find the acceleration of the stone, we can use the centripetal acceleration formula:
Acceleration (a) = (v^2) / r
Where:
- v represents the velocity of the stone
- r represents the radius of the circular path
First, let's convert the mass of the stone from grams to kilograms:
Mass (m) = 50g = 50g / 1000 = 0.05kg
Next, we can calculate the velocity (v) of the stone:
Velocity (v) = 2m/s
Now, let's convert the radius of the circle from centimeters to meters:
Radius (r) = 50cm = 50cm / 100 = 0.5m
Finally, we can calculate the acceleration (a) using the formula:
Acceleration (a) = (v^2) / r
a = (2^2) / 0.5
a = 4 / 0.5
a = 8 m/s^2
Therefore, the acceleration of the stone is 8 m/s^2.
To find the acceleration of the stone, we need to use the formula for centripetal acceleration:
a = v² / r
where
a is the centripetal acceleration,
v is the velocity of the stone, and
r is the radius of the circular path.
First, let's convert the mass of the stone to kilograms:
Mass = 50g = 0.05kg (since 1kg = 1000g)
Next, we need to convert the radius from centimeters to meters:
Radius = 50cm = 0.5m (since 1m = 100cm)
Now we can calculate the acceleration:
a = (2m/s)² / 0.5m
= 4 m²/s² / 0.5m
= 8 m/s²
Therefore, the acceleration of the stone is 8 m/s².