MATH Calculus Homework
posted by Claire .
Find the area of the region between the curve y^2=4x and the line x=3.

ok, sketch it.
area=INT2ydx from x=0 to 3
area=INT 2*sqrt(4x) dx
= INT 2*2sqrtx dx from x=0 to x^3
= 4*2/3 x^3 over limits
= 8/3 *27
check my work 
I sorry but I don't undestand. What would be f(x) and g(x)?

I have no idea what you mean by F(x) or g(x).

I'm sorry. For the equation that I have to use for this it is:
Integral symbol(f(x)g(x))dx 
Sorry I posted into the wrong conversation, please ignore me. Thank you.

f(x)=sqrt(4x) g(x)=sqrt(4x)
f(x)g(x)=2*f(x) 
Why is g(x)=sqrt(4x)?

sketch it!
sqrt4x=+ 2sqrtx 
Oh I forgot about the ± sign. THANK YOU!!
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