MATH Calculus Homework
posted by Claire .
Find the area of the region between the curve y^2=4x and the line x=3.
ok, sketch it.
area=INT2ydx from x=0 to 3
area=INT 2*sqrt(4x) dx
= INT 2*2sqrtx dx from x=0 to x^3
= 4*2/3 x^3 over limits
= 8/3 *27
check my work
I sorry but I don't undestand. What would be f(x) and g(x)?
I have no idea what you mean by F(x) or g(x).
I'm sorry. For the equation that I have to use for this it is:
Sorry I posted into the wrong conversation, please ignore me. Thank you.
Why is g(x)=-sqrt(4x)?
Oh I forgot about the ± sign. THANK YOU!!