A limited access highway had an access reduction and lost 1/13 of its exits. If 264 of its exits were left after the reduction how many exits were there originally?
284
(1 - 1/13)x = 264
Solve for x.
To calculate the number of exits originally on the limited access highway, we need to find the reciprocal of the fraction that represents the reduction in exits.
1/13 represents the fraction of exits that were lost.
So, the reciprocal of 1/13 is 13/1.
If we multiply the number of remaining exits (264) by the reciprocal (13/1), we can calculate the original number of exits.
264 * (13/1) = 3432.
Therefore, there were originally 3432 exits on the limited access highway.
To solve this problem, we need to work backwards. We know that after the reduction, there were 264 exits, which represents 1/13 of the original exits.
Let's represent the original number of exits as "x".
So, we can set up the equation:
1/13 * x = 264
To solve for x, we need to isolate it on one side of the equation.
Multiplying both sides of the equation by 13 will eliminate the fraction:
x = 264 * 13
x = 3432
Therefore, the original number of exits on the limited access highway was 3432.