Find the area of the region between the curve y^2=4x and the line x=3.
the curves intersect at (3,√12) and (3,-√12)
So, the area is just
∫[-√12,√12] 3-x dy
= ∫[-√12,√12] 3 - y^2/4 dy
and that should be a cinch
So, the area is just
∫[-√12,√12] 3-x dy
= ∫[-√12,√12] 3 - y^2/4 dy
and that should be a cinch