A gas occupying a volume of 664 mL at a pressure of 0.970 atm is allowed to expand at constant temperature until its pressure reaches 0.541 atm. What is its final volume?
See your post below.
To find the final volume of the gas, we can use the combined gas law equation:
P1 * V1 / T1 = P2 * V2 / T2
Where:
P1 = initial pressure (0.970 atm)
V1 = initial volume (664 mL)
T1 = initial temperature (constant)
P2 = final pressure (0.541 atm)
V2 = final volume (unknown)
T2 = final temperature (constant)
Since the temperature is constant, we can eliminate it from the equation:
P1 * V1 = P2 * V2
Now, let's plug in the values we know:
(0.970 atm) * (664 mL) = (0.541 atm) * V2
Now, we can solve for V2 by dividing both sides of the equation by (0.541 atm):
V2 = (0.970 atm * 664 mL) / (0.541 atm)
V2 ≈ 1191.130 mL
Therefore, the final volume of the gas is approximately 1191.130 mL.