What is the simplified form of (2a2b)2 (3ab3c)/4a4b8c2
Online "^" is used to indicate and exponent, e.g., x^2 = x squared.
Online, “*” is used to indicate multiplication to avoid confusion with “x” as an unknown.
Do you mean
(2a^2*b)^2 * (3ab^3*c)/(4a^4 * b^8 * c^2)
or
(2a*2b)^2 * 3ab * 3c /4a * 4b * 8c^2
or something else?
i know right i have a test review with this stupid question
To find the simplified form of the given expression, we need to simplify each term separately and then combine like terms, if possible. Let's break it down step by step.
First, let's simplify (2a^2b)^2:
To simplify a term raised to a power, we need to multiply the exponents. In this case, we have (2a^2b)^2, which means we multiply the exponents 2 and 2 separately from the base term 2a^2b.
Simplifying (2a^2b)^2:
(2a^2b)^2 = 2^2 * (a^2)^2 * (b)^2
= 4 * a^(2*2) * b^2
= 4 * a^4 * b^2
Next, let's simplify (3ab^3c):
Since there is no exponent in this term, we can consider each variable separately.
Simplifying (3ab^3c):
= 3 * a * b^3 * c
= 3abc * b^2
= 3abc^1 * b^2
= 3ab^2c
Now, let's simplify 4a^4b^8c^2:
There are no parentheses or exponents in this term, so we can leave it as is.
Combining all the terms, we have:
(4 * a^4 * b^2 * 3ab^2c) / (4a^4b^8c^2)
Now let's simplify the expression further by canceling out common factors. Here's how:
Start with the numerator: 4 * a^4 * b^2 * 3ab^2c
In the numerator, we can cancel out 4 and 3 by dividing them, leaving only the factors to simplify:
(a^4 * b^2 * ab^2c) / 1
Now, let's simplify the denominator: 4a^4b^8c^2
In the denominator, we have no common factors to cancel out.
Combining the numerator and the denominator, we get:
(a^4 * b^2 * ab^2c) / (4a^4b^8c^2)
To simplify further, we can simplify each variable separately:
(a^4 * a * b^2 * b^2 * c) / (4 * a^4 * b^8 * c^2)
Cancelling out common factors in the numerator and denominator, we can simplify further:
1/ (4 * b^4 * c)
Therefore, the simplified form of the expression (2a^2b)^2 * (3ab^3c) / (4a^4b^8c^2) is:
1/ (4 * b^4 * c)