The activity of a sample of 35(upper#) 16(lower#)Sulfer (T 1/2= 7.55x10^6 s) is 2.51x10^5 decays per second.

WHat is the mass of the sample?

m= in grams

PLease help me out...Thank you! :)

To find the mass of the sample, we need to use the radioactive decay equation:

Activity = decay constant (λ) * number of radioactive atoms

The decay constant (λ) can be calculated using the half-life (T1/2) of the radioactive material:

λ = ln(2) / T1/2

First, let's calculate the decay constant (λ):

λ = ln(2) / T1/2
= ln(2) / (7.55x10^6 seconds)

Next, we can find the number of radioactive atoms using the activity:

Activity = λ * number of radioactive atoms
2.51x10^5 decays per second = λ * number of radioactive atoms

Now we can solve for the number of radioactive atoms:

number of radioactive atoms = Activity / λ

Finally, we can calculate the mass of the sample using the number of radioactive atoms and the molar mass of sulfur (16 g/mol):

mass of sample = number of radioactive atoms * molar mass

Remember, you need to convert the activity from decays per second to per grams using Avogadro's number (6.022x10^23 atoms/mol).

I hope this explanation helps! If you have any further questions, feel free to ask.