The activity of a sample of 35(upper#) 16(lower#)Sulfer (T 1/2= 7.55x10^6 s) is 2.51x10^5 decays per second.

WHat is the mass of the sample?

m= in grams

PLease help me out...Thank you! :)

To find the mass of the sample, we need to use the radioactive decay equation:

Activity (A) = λ * N

where A is the activity, λ is the decay constant, and N is the number of radioactive atoms.

We can rearrange this equation to solve for N:

N = A / λ

First, we need to find the decay constant (λ). The decay constant is related to the half-life (T_1/2) as follows:

λ = ln(2) / T_1/2

Substituting the given half-life value, we can calculate λ:

λ = ln(2) / (7.55 × 10^6 s)

Now we can find the number of radioactive atoms (N):

N = 2.51 × 10^5 decays per second / λ

Finally, to find the mass (m), we can use the radioactive decay equation:

m = N * molar mass / Avogadro's number

Where the molar mass is the mass of one mole of 16Sulfer and Avogadro's number is the number of atoms in one mole.

By substituting the values, you can calculate the mass of the sample in grams.