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A firm manufactures light bulbs and those that come out of the assembly line are either defective or good. Every five bulbs that come out, 1 is defective. If 3 bulbs are selected at random, what is the probability that:

(i) All 3 are defective
(ii) All 3 are good
(iii) The first selected is defective
(iv) 1 defective and 2 good
(v) 2 defective and 1 good
(vi) At most 2 are good

  • Math -

    If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

    1. (1/5)^3 = ?

    2. (4/5)^3 = ?

    3. 1/5

    4. 1/5 * 4/5 * 4/5 = ?

    5. You do it, using similar process.

    6. This is none good, one good or 2 good.

    Either-or probabilities are found by adding the individual probabilities.

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