What is x^2+6x-91 when factored ???!!

-13 and 7

(x-7)*(x+13)

To factor the quadratic expression x^2 + 6x - 91, we need to find two binomial expressions that, when multiplied together, give us the original expression.

To start factoring, we need to look for two numbers whose sum is equal to the coefficient of the middle term (in this case, 6) and whose product is equal to the product of the coefficients of the first and last terms (in this case, 1 * -91 = -91).

Looking for factors of 91, we find that the pair (13, -7) satisfies both requirements. So, we can rewrite the quadratic expression as follows:

x^2 + 13x - 7x - 91

Now, we group the terms and factor them separately:

(x^2 + 13x) + (-7x - 91)

Taking the common factor from the first pair of terms and the second pair of terms, we get:

x(x + 13) - 7(x + 13)

Now, we can see that both terms have a factor of (x + 13), so we can factor it out:

(x - 7)(x + 13)

Therefore, x^2 + 6x - 91 can be factored as (x - 7)(x + 13).