Pre-Calculus

posted by .

45. log b sqrt 7x

46. log b sqrt (3/y)

Could someone please explain these?

  • Pre-Calculus -

    45.
    logb √(7x)
    = logb (7x)^(1/2)
    =(1/2 logb (7x)
    = (1/2) ( logb 7 + logb x)

    do #46 the same way,
    except recall that log(A/B) = logA - logB

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. TRig WIth LoGs help1!!

    i have problem i can't solve and the book is no help.. anyone got osme hints or somehting i could start off doing?
  2. Math Help please!!

    Could someone show me how to solve these problems step by step.... I am confused on how to fully break this down to simpliest terms sqrt 3 * sqrt 15= sqrt 6 * sqrt 8 = sqrt 20 * sqrt 5 = since both terms are sqrt , you can combine …
  3. Calculus

    so we are doing integrals and I have this question on my assignment and I can't seem to get it, because we have the trig substituion rules, but the number isn't even so its not a perfect square and I just cant get it, so any help would …
  4. Calculus

    Evaluate the indefinite integral: 8x-x^2. I got this but I the homework system says its wrong:sqrt((-x-8)x)/(2*sqrt(x-8)*sqrt(x))*(((sqrt(x-8)*(x-4)*sqrt(x))-32*log(sqrt(x-8)+sqrt(x))
  5. Logarithm Functions

    Solve this log function: a) log (sqrt(x^2-3x))=0.5 b) log (sqrt(x^2+48x))=1
  6. Math Help Please

    Which of the following expressions is equal to log (x sqrt-y)/z^5 A. log x + log (1/2) + log y– log 5 – log z B. log [x + (1/2)y – 5z] C. log x + (1/2)log y – 5 log z d. [(1/2) log x log y]/(5 log z)
  7. math

    Logarithm!!! Select all of the following that are true statements: (a) log(2x) = log(2) + log(x) (b) log(3x) = 3 log(x) (c) log(12y) = 2 log(2) + log(3y) (d) log(5y) = log(20y) – log(4) (e) log(x) = log(5x) – log(5) (f) ln(25) …
  8. Calculus

    Could someone please explain this to me? Differentiate. h(u)= 10^(sqrt(u)) h'(u)= 10^(sqrt(u))*log(10)(d/du(sqrt(u))) h'(u)= 10^(sqrt(u))*((1)/(2*sqrt(u)))*log(10)
  9. Calculus

    S=Integral xdx/sqrt(x-1). I have proceeded thus- Put sqrt(x-1)=u then x=u^2+1 and dx/sqrt(x-1)=2du. S=(u^2+1)2du/u =(2u+2/u)du=u^2+2 log u +C =(x-1)+ 2 log sqrt(x-1)=(x-1)+log(x-1)+C Required answer is 2/3*(x+2)sqrt(x-1)+C Have I proceeded …
  10. Calculus 3

    I need help writing the series 4 + 1/5 + .3 + 1/(3 + sqrt 2) + 1/(9+ sqrt 3) + 1/(27 + sqrt 4) + 1/(81 + sqrt 5 .... I have played with using irrational numbers, natural log and a vast variety of exponential arrangements. Any help …

More Similar Questions