a 35.0ml sample of 37% hcl solution has a density of 1.18g/ml. the sample is diluted to a volume of 0.125L. what is the molarity of the final solution ?
What's the molarity of the HCl?
1.18 g/mL x 1000 mL x 037 x (1 mol/36.5g) = ? M
Then mL1 x M1 = mL2 x M2
DrBob222 i need the solution of this numerical problem step by step please
John, I did everything but draw a picture and we can't draw pictures on this forum.
The first part is 1.18 x 1000 x 0.37 x (1/36.5) = APPROXIMATELY 12 M but you do the math yourself and use your number.
Then
35.0 = mL1
12 = M1
125 = mL2
M2 = unknown
35.0 x 12 = 125 mL x M2
Solve for M2 of the diluted solution.
Your answer should be about 3.5M.
To find the molarity of the final solution, we need to determine the number of moles of the solute (HCl) and then divide it by the volume of the solution in liters (0.125L).
First, let's calculate the number of moles of HCl in the 35.0ml sample.
The given concentration of the HCl solution is 37%. This means that there are 37g of HCl in 100 ml of solution.
To convert the volume of the sample to grams of HCl, we use the density of the solution:
Mass = Volume x Density
Mass = 35.0ml x 1.18g/ml
Now, we can convert the mass of the sample to moles:
Moles = Mass / Molar Mass
The molar mass of HCl is the sum of the molar masses of hydrogen (1.008 g/mol) and chlorine (35.453 g/mol).
After finding the moles of HCl in the 35.0ml sample, we can calculate the molarity of the final solution:
Molarity = Moles of HCl / Volume of Solution (in L)
Let's plug in the values and calculate the molarity.