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hurry!, find the value of x in 2^x + 2^x + 2^x = 192. with explanation.

  • math -

    2 ^ x + 2 ^ x + 2 ^ x = 192

    3 * 2 ^ x = 192 Divide both sides by 3

    3 * 2 ^ x / 3 = 192 / 3

    2 ^ x = 64

    x = 6 becouse 2 ^ 6 = 64


    OR

    2 ^ x = 64

    x * log ( 2 ) = log ( 64 ) Divide both sides by log ( 2 )

    x = log ( 64 ) / log ( 2 )

    x = 4.158883 / 0.693147

    x = 6


    log ( x ) is " Natural logarithm " ( Logarithm with base e )

    x =

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