How many moles of P4O10 are produced when we react 8 moles of phosphorous with oxygen? I know the answer is:
4 mol P produces 1 mol P4O10
8 mol P produces 2 mol P4O10.
Or, 1 mol P4O10 x (8 mol P / 4 mol P) = 2 mol P4O10.
but, what is the balanced equation?
Note the correct spelling of phosphorus.
P4 + 5O2 ==> P4O10
The "answers" in your post make me think you are using phosphorus as P when in fact it is P4. Therefore,
8 mols P4 x (1 mol P4O10/1 mol P4) = 8 mols P4O10
Well, before I give you the balanced equation, let me just say that chemistry jokes are never stale, they're always Avogadro's number-one choice. Now, for the balanced equation:
4P + 5O2 → 2P4O10
There you go! A perfectly balanced equation to go along with your moles of P4O10. Keep rockin' the chemistry!
The balanced equation for the reaction between phosphorus and oxygen to form P4O10 is:
4 P + 5 O2 → 2 P4O10
This equation shows that for every 4 moles of phosphorus (P), 5 moles of oxygen gas (O2) are needed to produce 2 moles of P4O10.
To determine the balanced equation for the reaction between phosphorus (P) and oxygen (O2) to form phosphorus pentoxide (P4O10), we need to follow a step-by-step process.
1. Write down the reactants and products:
P + O2 → P4O10
2. Start with the most complex molecule in the equation, which is P4O10.
3. Count the number of atoms of each element on the left side of the equation (reactants) and the right side (products).
Reactants:
- Phosphorus (P): 1 atom
- Oxygen (O): 2 atoms
Products:
- Phosphorus (P): 4 atoms
- Oxygen (O): 10 atoms
4. Balance the atoms on each side by adjusting the coefficients. In this case, since we only have one phosphorus atom on the reactant side and four on the product side, we need to add a coefficient of 4 in front of P to balance the phosphorus atoms.
The balanced equation is:
4P + 5O2 → P4O10