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Chemistry
Stoichiometry
Mole-to-mole ratio calculation
for the reaction 2NaOH + h2SO4 yieda 2H2O + Na2SO4 if .80 moles of NaOH are used, how many moles of H2SO4 must be used?
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mols H2SO4 = 1/2 mol NaOH
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H2SO4 + 2NaOH = 2H2O + Na2SO4 n(H2SO4) = 9.65g/98g/mol = 0.098 n(NaOH) = 6.10g/40g/mol = 0.15 mol 1 mole of H2SO4 is = to 1
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what is the excess reactant of H2SO4+2NaOH->Na2SO4+2H2O
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This site doesn't handle spaces very well. I assume you mean 0.4 L of 0.025M H2SO4 with 0.4 L of
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i have no idea how to do this!
Calculate the volume of the specified titrant required to neutralize 35 ml of .4 M NaOH. Titrant:
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Write the molecular equation. H2SO4 + 2NaOH
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for asking.
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