what is the volume in liters in H2gas produced at 24 degree celsius and 835 mmhg from the reaction of 12g of many thanks
12 grams of many thanks?
To find the volume of gas produced, we can use the ideal gas law equation, which states:
PV = nRT
Where:
P = pressure of the gas (in atm)
V = volume of the gas (in liters)
n = number of moles of the gas
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature of the gas (in Kelvin)
First, let's convert the given temperature from Celsius to Kelvin:
T(°C) = T(K) - 273.15
T(K) = T(°C) + 273.15
T(K) = 24 °C + 273.15 = 297.15 K
Next, we can calculate the number of moles of H2 gas:
n = mass / molar mass
The molar mass of H2 is:
2 g/mol (since H2 is diatomic)
n = 12 g / 2 g/mol = 6 mol
Now, we can plug in the values into the ideal gas law equation to find the volume.
PV = nRT
V = nRT / P
V = (6 mol * 0.0821 L.atm/mol.K * 297.15 K) / 835 mmHg
Note: We need to convert the pressure from mmHg to atm, since the ideal gas constant is in atm units.
1 atm = 760 mmHg.
P(atm) = P(mmHg) / 760 mmHg/atm
P(atm) = 835 mmHg / 760 mmHg/atm = 1.097 atm
Now we can substitute the values to find the volume:
V = (6 mol * 0.0821 L.atm/mol.K * 297.15 K) / 1.097 atm
Calculating this expression, we get the volume of H2 gas produced in liters.