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If the length of a rectangle is 4 more than 3 times the width, and the perimeter is 32 meters, what are its dimensions?

Please enter your answer as two numbers without the units, separated by a comma.

  • math -

    width --- x
    length --- 3x + 4

    Perimeter = 2width + 2lengths

    take it from there

  • math -

    P = 2L + 2W

    P = 2(3W + 4) + 2W

    32 = 6W + 8 + 2W

    24 = 8W

    3 = W

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