Physics

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Composite bar with end load (two segments)

The composite bar BCD in the figure is composed of an inner aluminum cylindrical core of length 2L=2 m and radius R=1 cm and a sleeve of steel of length L=1 m and thickness R=1 cm surrounding the aluminum core in the CD section of the bar. The Young’s moduli are: E(Al) = 70 GPa, and E(steel)=210 GPa. The bar is fixed at B and a concentrated tensile load F is applied at the free end D. The resulting total elongation of bar BCD, is δ=1 cm. Determine the normal stress in the steel sleeve. (in MPa)

i[dot]imgur[dot]com/McHq9LJ.png

  • Physics -

    Helpless it is, 184 MPA

    Do you have figured out Problem 1 and 2?

  • Physics -

    Anyone?

  • Physics -

    Problem 1 and 2?

  • Physics -

    Problem 1 and 2 please!

  • Physics -

    Determine the normal stress in the steel sleeve.
    Obtain the numerical value of the displacement of section.
    pllllllllllllllllllllz help?

  • Physics -

    -86.8 MPa

  • Physics -

    problem3_1 second part,
    Obtain the numerical value of the displacement of section c....!
    plz help?

  • Physics -

    @jojo

    0.4mm

  • Physics -

    3_2(a)
    3_2(b)
    plz help.

  • Physics -

    3_3 problem
    plz help.

  • Physics -

    HW3_2A

    (2*p_0*L)/27-p_0*(L/3-x+(3*x^2)/(4*L))

    (p_0*2*L/27)

    HW3_2B

    (2*p_0*L*x)/(27*E*A)-p_0/(E*A)*((L*x)/3-x^2/2+x^3/(4*L))

    p_0*2*L/(27*E*A)*(x-L)

  • Physics -

    HW3_3A
    u1 = -a*L*x1;

    u2 = 2*a*(x2.^2-L*x2);

    HW3_3B
    N1 = -3*a*L*A*E+0*x1;

    N2 = 6*a*A*E*(2*x2-L);

    HW3_3C
    fx1 = 0 + 0*x1;

    fx2 = -12*a*A*E + 0*x2;

    HW3_3D1
    Fx=-3*a*L*A*E

    x=L/2

    HW3_3D2
    R(B)=3*a*A*E*L

    R(C)= 6*a*A*E*L

  • Physics -

    E2_2:
    E2_3:
    PLZ help

  • Physics -

    E2_2
    1)epsilon_0*x/L*(L-x/2)
    2)epsilon_0*L/2
    3)-epsilon_0/(2*L)*(L-x)^2
    4)epsilon_0*L/2

    E2_3
    1)112
    2)0.001
    3)-0.004
    4)-0.004

  • Physics -

    E3_1?
    HW3_4?

  • Physics -

    HW3_3 Inverse PROBLEM ON STATICALLY INDETERMINATE COMPOSITE BAR (PART 4)

  • Physics -

    HW3_4B: 0.5

  • Physics -

    E3_1
    1)-50
    2)50,100
    3)12*a*L*E_1*A_2*(x/L-1),-30
    4)0
    5)-12*E_1*A_2*a


    HW3_3D1
    Fx=-3*a*L*A*E
    x=L/2

    HW3_3D2
    Rx(B)=3*a*A*E*L
    Rx(C)= 6*a*A*E*L

  • Physics -

    HW3_4A
    2.66

    HW3_4B
    0.49

  • Physics -

    problem hw3_1b
    second part?
    anyone gave the answer?

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    thanks alot regz.

  • Physics -

    thanks regz.

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    thanks anonymous.

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    problem 4_1?
    SD truss problem with the method of joints...............!

  • Physics -

    hw3_1(b)
    0.4mm
    @heyyo

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    plz help
    problem 4_1?

  • Physics -

    HW4_1
    1)
    -1.17
    -1.17
    1.4142
    0.936
    2.35
    2)
    -1.414
    0.702
    0.702
    3)
    -4.05
    -4.05
    2.59
    6.49

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