Science Chemistry
At 20 degree celsius, Ka for an unknown monoprotic weak acid is 0.00088. Calculate the Delta G (in kJ/mol) for the reaction of this unknown acid with water.
HA(aq) + H2O(l) <--> H3O+(aq) + A-(aq)
You can ask a new question or answer this question .
Similar Questions
Top answer:
the initial acid molarity is ... [HA] = .112 * (22.32 / 25.00) = 0.100 [H+] = 10^(-2.87) = .00135
Read more.
Weak Acid 1.) The pH of a 0.060M weak monoprotic acid HA is 3.44. Calculate the Ka of the acid. 2.) The pH of 0.100M solution of
Top answer:
I have shown you how to do these below. If you want to post your answer I can check it
Read more.
Weak Acid 1.) The pH of a 0.060M weak monoprotic acid HA is 3.44. Calculate the Ka of the acid. 2.) The pH of 0.100M solution of
Top answer:
I have shown you how to do these below. If you want to post your answer I can check it.
Read more.
Top answer:
So (H^+) = 0.04 x 0.14 = ?? (X^-) is the same. (HX) = either, 0.04-(0.04*0.14) OR 0.04*0.86 (HX)
Read more.
Top answer:
mols base = M x L = ? For a monoprotic acid mols acid = mols base mols acid = grams acid/molar mass.
Read more.
A. Strong Base 1.) What is the concentration of a solution of KOH for which the pH is 11.89? 2.) What is the pH of a 0.011M
Top answer:
Please do not put long lists of questions as it is unlikely that they will all get answered. Have
Read more.
Top answer:
HA ==> H^+ + A^- Ka = (H^+)(A^-)/(HA) You know HA is 0.490. If it is ionized 2.80%, then H^+ and A^-
Read more.
Top answer:
a) HA + NaOH ==> H2O + NaA b) moles NaOH = M x L = ?? Using the coefficients in the balanced
Read more.
Top answer:
I tried: 0.00052224=0.1777/x 0.00052224=380/x
Read more.
Top answer:
My calculator is broken. You calculate H^+ from pH = -log(H^+). I will call that value, whatever it
Read more.
