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Find the area of the triangle with sides 8.6 cm, 9.1cm and 9.7cm. First find the size of one of the angles.

  • Maths -

    Use the law of cosines.

    cosA = (-a^2+b^2+c^2)/2bc.
    cosA=(-(8.6)^2+(9.1)^2+(9.7)^2)/176.54 =
    0.58310.
    A = 54.33o.

    Area = 0.5*bc*sinA.
    Area=0.5*9.1*9.7*sin(54.33) = 35.9 cm^2

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