The boom weighs 2450 and is attached to a friction less pivot at its lower end. It is not uniform; the distance of its center of gravity from the pivot is 39.0 of its length.

Question

The boom weighs 2450 and is attached to a friction less pivot at its lower end. It is not uniform; the distance of its center of gravity from the pivot is 39.0 of its length.

What is the tension in the guy wire?

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Answer 1

assume boom weighs 2450 Newtons

HAVE to Know Length of boom (I will call it L)

clockwise moments about base of boom
5000 L cos 60 + 2450 (39) cos 60

counterclockwise moments
T L sin 60
so
T = (5000 L + 2450(39) )cos 60/(L sin 60)

Answer 2

I apologize, but as an AI text-based bot, I'm unable to view or access external links or images. However, I can still guide you through the steps to solve this problem.

To find the tension in the guy wire, we need to use the principle of moments. The principle of moments states that the sum of the clockwise moments about a point is equal to the sum of the anticlockwise moments about the same point.

In this case, let's consider the pivot point as the reference point. We have two forces acting on the boom: the weight of the boom (2450 N) acting downwards through its center of gravity and the tension in the guy wire acting upwards from a point on the boom.

To balance the moments, the clockwise moment caused by the weight needs to be equal to the anticlockwise moment caused by the tension in the guy wire.

Let's denote the length of the boom (from pivot to the center of gravity) as L, and the distance of the center of gravity from the pivot as 0.39L (as mentioned in the question).

The clockwise moment caused by the weight of the boom is given by the formula:

Clockwise Moment = Weight * Distance

Clockwise Moment = 2450 N * 0.39L

The anticlockwise moment caused by the tension in the guy wire is given by:

Anticlockwise Moment = Tension * Length

Now, since the boom is not rotating or moving, the clockwise moment is equal to the anticlockwise moment. So we can equate the two moments:

2450 N * 0.39L = Tension * Length

Now, you can solve this equation to find the tension in the guy wire by substituting the given values.