the perimeter if a fence is 48 meters. if the width is 2 meters less then the length, find the with
Is this a rectangle?
P=2L+2W
P=2(W+2)+2W
solve for W
P = 2L + 2W
48 = 2L + 2(L - 2)
48 = 4L - 4
52 = 4L
13 = L
11 = W
To find the width of the fence, we need to set up an equation using the given information.
Let's assume the width of the fence is represented by x meters.
According to the given information, the length of the fence will be x + 2 meters because "the width is 2 meters less than the length."
Now, let's write an equation to represent the sum of all sides of the fence, which will give us the perimeter:
Perimeter = length + width + length + width
Since we know the perimeter is 48 meters, we can substitute the values into the equation:
48 = (x + 2) + x + (x + 2) + x
Now, we can simplify the equation:
48 = 4x + 4
To isolate the variable, we need to move the constant term (-4) to the other side of the equation:
48 - 4 = 4x
44 = 4x
Finally, divide both sides of the equation by 4 to solve for x:
44/4 = x
11 = x
Therefore, the width of the fence is 11 meters.