how many solutions (answers) does this equation has?
sinx=sin1
infinitely many
x=1
x=2pi+1
x=4pi+1
...
sinx has period 2pi so adding 2pi to any solution gives another solution
sinx=sin1
x=1
x=2pi+1
x=4pi+1
...
sinx has period 2pi so adding 2pi to any solution gives another solution