Chemistry

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Calculate the percent ionization of 0.140 M lactic acid in a solution containing 8.5×10−3 M sodium lactate.

  • Chemistry -

    Call lactic acid HL and sodium lactate NaL.
    ..........HL ==> H^+ + L^-
    I.........0.140...0...0.0085
    C.........-x......x.....x
    E.......0140-x....x...0.0085+x

    Substitute into the Ka expression for HL and solve for x = (H^+).It may be necessary to solve a quadratic.
    Then %ion = [(H^+)/0.140]*100 = ?

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