an electron above the earth is balanced by the gravitational force and the electric field of the earth. find the electric field of the earth.
at the separation should two equal charges, 1.0c each, be placed so that the force between them equal the weight of a 50 kg person?
To find the electric field of the Earth, we need to first set up an equation that balances the gravitational force and the electric field.
The gravitational force acting on the electron is given by Newton's Law of Universal Gravitation:
Fg = G * (Me * Me) / R^2.
where Fg is the gravitational force, G is the gravitational constant, Me is the mass of the Earth, and R is the distance from the electron to the center of the Earth.
On the other hand, the electric force acting on the electron is given by:
Fe = q * E,
where Fe is the electric force, q is the charge of the electron, and E is the electric field.
Since the electron is balanced, the two forces are equal in magnitude:
Fg = Fe.
Now we can equate the expressions for gravitational and electric forces:
G * (Me * Me) / R^2 = q * E.
To find the electric field E, we rearrange the equation:
E = [G * (Me * Me) / (q * R^2)].
Given the values of G, Me, q, and R, we can substitute them into the equation to find the value of E.
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