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Algebra
Equations and Expressions
Polynomial expressions
3ab+2a+5b
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Let a and b be real numbers such that a^3 + 3ab^2 = 679 and a^3 - 3ab^2 = 673. Find a - b.
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6
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If 3ab=6, what is the value of a in terms of b?
a. 2 b. 2/b c. 2b^2 d. 2b e. 2b^2 My answer is d, but not sure, anyone can tell
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3ab=6 ab =2 a =2/b answer b
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add (4a^2b-3ab^2+2ab+5) and (2a^2b+3ab^2-7ab)
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To add the given expressions: (4a^2b-3ab^2+2ab+5) + (2a^2b+3ab^2-7ab) We can combine like terms by
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(4a^2b-3ab^2+2ab+5)+(2a^2b+3ab^2-7ab)
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Combining like terms, we have: (4a^2b - 3ab^2 + 2ab + 5) + (2a^2b + 3ab^2 - 7ab) = 4a^2b + 2a^2b -
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What is the value of a in terms of b?
3ab=6 Divide both sides of that equation by 3b to get an equation with only a on one side.
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Well, if we divide the equation 3ab=6 by 3b, we get ab=2. So, the value of a in terms of b would be
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(6a^4b+ab^3)+(3ab^3-6a^4b)
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Combine the like terms (6a^4b - 6a^4b) + (ab^3 + 3ab^3) = 0a^4b + 4ab^3 = 4ab^3
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3ab(4a^2-7b^3)
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Expanding the expression, we have: 3ab(4a^2 - 7b^3) = 3ab * 4a^2 - 3ab * 7b^3 Simplifying, we get: =
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Simplify.
-(3ab^2)^-3
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The negative exponent means that we need to take the reciprocal of the expression raised to the
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How many factors are in 3ab
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The expression 3ab does not have any factors because it is not a number or a combination of numbers
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4a³b*(3ab)–²
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To simplify the expression 4a³b*(3ab)–², we can first simplify the term (3ab)–², which means
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