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Two angles of an isosceles triangle are 68∘ and x∘. What is the sum of all the (distinct) possible values of x?

all the angles on a triangle egual 180 degrees so take 68 times 2 then subtract that by 180

there are two possible configurations

x+x+68 = 180: x=56
x+68+68 = 180: x=44

so, 56+44 = 100

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