# algebra

posted by .

find the vertex of 400-16tsquared

• algebra -

Y = -16t^2 + 400
h = Xv = -B/2A - 0/-32 = 0.
k = Yv = -16*0^2 + 400 = 400.

V(0,400).

## Similar Questions

1. ### Algebra Functions

I cannot for the life of me remember how to do this- Find the vertex of the graphs of the functions: Function #1: y=(x-4)(x+2) AND Function #2: y=2x^2-4x+1 Can someone help me get it PLz! OK - to find the vertex of these functions …
2. ### algebra

determine the vertex for the function y=2x^2+5x-3 for y = ax^2 + bx + c, the x value of the vertex is -b/(2a) sub that x into your equation to find the y. Another way is to complete the square. so for yours, x = -5/4 etc. a third way, …
3. ### Algebra HW

Find the vertex of the function y = –x2 + 2x + 8. it shows me different points as the answer. Im not sure how to find that point. Here are the points: (1,7) or (1,9) or (4,-2) or (-1,-9) Answered in a previous post. Here it is again: …
4. ### Algebra

Identify the vertex and the axis of symmetry for the graph of y=5(x-2)^2 + 3. a) vertex (2,3); x = -2 b) vertex (-2,-3); x = 2 c) vertex (2,3); x = 2 d) vertex (-2,-3); x = -2 I have no idea how to solve this problem! Please help. …
5. ### algebra

I would like to have some help on this problem please. I'm so post to find the vertex and axis of the parabola.Does anyone have an idea?
6. ### algebra

find the vertex of 400-16tsquared
7. ### Algebra

Find the equation of the parabola with its vertex at (h,k). Vertex: (-2.1) Focus: (-5,1) I know I put it into (y-k)^2=4(p)(x-h) so (y-1)^2=4(p)(x+2). How do I find the value of p?
8. ### Algebra

Find the equation of the parabola with its vertex at (h,k). Vertex: (-2.1) Focus: (-5,1) I know I put it into (y-k)^2=4(p)(x-h) so (y-1)^2=4(p)(x+2). How do I find the value of p?
9. ### Algebra

For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6. Show your work. y = -2x2 + 2x +2 -(1/2)y=x^2-x-1 (-1/2)y+1=x^2-x (-1/2)y+1=(x-1/2)^2-14 (-1/2)y=(x-1/2)^2-5/4 y=-2(x-1/2)^2+5/2 …
10. ### Algebra

For the given quadratic equation convert into vertex form, find the vertex, and find the value for x = 6. Show your work. y = -2x2 + 2x +2 -(1/2)y = x^2 - x - 1 (-1/2)y + 1 = x^2 - x (-1/2)y + 1 = (x - 1/2)^2 - 1/4 (-1/2)y = (x-1/2)^2 …

More Similar Questions

Post a New Question