PLEASE HELP CHEM!!

posted by .

5.6 x 10-6 mol of A and 5 x 10-5 mol of B are mixed in a 200 mL flask. The system is represented by the equation:
2A(G) + B(G) <--> 3C(G)

At equilibrium, there is 4.8 x 10-5 mol of B. Calculate the value of the equilibrium constant.

  • PLEASE HELP CHEM!! -

    (A) = 5.6E-6/0.2 = 2.8E-5M
    (B) = 5E-5/0.2 = 2.5E-4M

    .........2A + B ==> 3C
    I.....2.8E-5..2.5E-4..0
    C.......-2x...-x....3x
    E...2.8E-5-2x..2.5E-4-x...3x

    We know B at equilibrium = 4.8E-5 mol/0.2L = 2.4E-4; therefore,
    2.5E-4-x = 2.4E-4
    Solve for x which lets you work out A and C at equilibrium. Then substitute into Keq expression and solve for K.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chem class

    Nitrosyl bromide decomposes according to the following equation. 2NOBr (g)(equilibrium arrow) 2NO (g) + Br2 (g) A sample of NOBr (0.64 mol) was placed in a 1.00-L flask containing no NO or Br2. At equilibrium the flask contained 0.46 …
  2. Chem 101

    At 600degrees Celcius, gaseous CO and Cl2 are mixed together in a 1.00 L closed container. At the instant they are mixed, their concentrations are CO=.25 mol/L and Cl2= .69 mol/L. After equilibrium is established, their concentrations …
  3. Chemistry

    5.6 x 10-6 mol of A and 5 x 10-5 mol of B are mixed in a 200 mL flask. The system is represented by the equation: 2A(g) + B(g) --> 3C(g) At equilibrium, there is 4.8 x 10-5 mol of B. Calculate the value of the equilibrium constant.
  4. Chemistry

    A system is represented by the following equation: 2A(aq) + B(aq) --> 3C(aq) At equilibrium, [C]=0.6 M. Calculate the value of K if initially 1 mol of A and 2 mol of B were placed in a 1 L flask.
  5. Chemistry

    PLEASE fully explain these...I've already tried to figure them out and failed terribly... thanks so much 4. 5.6 x 10-6 mol of A and 5 x 10-5 mol of B are mixed in a 200 mL flask. The system is represented by the equation: At equilibrium, …
  6. Chemistry

    4. 5.6 x 10-6 mol of A and 5 x 10-5 mol of B are mixed in a 200 mL flask. The system is represented by the equation: 2A + B --> 3C I 2.8x10-5 M 2.5x10-4 0 C -2x -x +3x E 2.8x10-5-2x 2.5x10-4-x 3x10-5 B = 2.5x10-4-x = 2.4x10-4 x …
  7. chemistry

    2NO (g) + Cl2 (g) <=> 2NOCl (g) (reversible) equilibrium constat = 1 x 10^7 @ certain temp NO = 2.8 x 10^-2 mol Cl2 = 1.4 x 10^-3 mol NOCl = 5.9 mol all mixed in a 1.4 L flask what is Qc and what direction will system go?
  8. CHEM- need help ASAP

    An equilibrium mixture in a 10.0 L flask contains 7.0 mol HI(g) and 1.0 mol each of I2(g) and H2(g). If 2.5 mol H2, 5.0 mol I2 and 2.0 mol HI are added to that equilibrium mixture how many moles of each gas will be present when equilibrium …
  9. AP Chem

    NO2 + H2 <-> NO + H2O [H2] = .30 mol/L [NO2] = .20 mol/L [NO] = [H20] = .70 mol/L @ 1000K A. What is the mole fraction of NO in the equilibrium mixture?
  10. chem 12

    1.0 mol of each of the gases, CO, H20, CO2 and H2 are placed in a 2.00L container and allowed to reach equilibrium. It is found at equilibrium 0.40 mol of CO is present. Calculate the value of K eq for the system. C0(g) + H20(g)--- …

More Similar Questions