# algerba 1

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4. The total value of the \$1 bills and \$5 bills in a cash box is \$124. There are 8 more \$5 bills than \$1 bills. How many of each are there?

• algerba 1 -

pretend \$1 is x
and \$5 is y

x+8=y *bc you have to add 8 \$1 to
have the same number of \$1 as \$5

1x+5y=124 *this is basically saying that there is an "x" number of \$1 bill plus a "y" number of \$5 will get u \$124

now use elimination:
since y=x+8 plug "x+8" as "y" in the other equation

1x+5(x+8)=124
1x+5x+40=124 *distribute
6x=84
x=14

now plug "x" into the first equation to find y:
x+8=y
14+8=y
y=22

this means that 14 \$1 and 22 \$5 will get you \$124

14+8=22 *correct
and
1(14)+5(22)=124 *correct

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