Question

If x=t^3 and y=3t^5, where t is any real number, what is the derivative of y with respect to x at x=125 ?

Answer 1

t=∛x =x^(1/3) =>

y=3x^5 = 3x^(5/3).

dy/dx =3•(5/3)•x^(2/3) =
=5 •125^(2/3)=525=125