A gas with a volume of 4.20 L at a pressure of 0.63 atm is allowed to expand until the volume raises to 95 L. What is the new pressure (in atm)?
The new pressure is 0.13 atm.
To find the new pressure, we can use the combined gas law formula:
(P1 * V1) / T1 = (P2 * V2) / T2
Given:
P1 = 0.63 atm (initial pressure)
V1 = 4.20 L (initial volume)
V2 = 95 L (final volume)
Let's assume that the temperature (T) remains constant. Therefore, we can rewrite the equation as:
P1 * V1 = P2 * V2
Now we can substitute the values:
(0.63 atm) * (4.20 L) = P2 * (95 L)
(0.63 * 4.20) / 95 = P2
The new pressure (P2) is approximately 0.0278 atm.
To determine the new pressure of the gas, we can use the combined gas law formula:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature (assumed constant)
P2 = final pressure (what we're trying to find)
V2 = final volume
T2 = final temperature (assumed constant)
In this case, the temperature is assumed constant, so we can rewrite the formula as:
P1 * V1 = P2 * V2
Now let's substitute the given values into the formula:
P1 = 0.63 atm
V1 = 4.20 L
V2 = 95 L
0.63 atm * 4.20 L = P2 * 95 L
Now we can solve for P2:
P2 = (0.63 atm * 4.20 L) / 95 L
P2 = 0.0279 atm (rounded to four decimal places)
Therefore, the new pressure of the gas is approximately 0.0279 atm.