posted by Shadow .
How much water must be added to 6 mL of a 0.05M stock solution to diltue it to 0.02M ?
The answerI got is 15 mL. Is this correct? Thanks
Close but no cigar.
6 mL x 0.05 = xmL*0.02
x mL = 15.0 mL which is the final volume. Therefore, you must add 9 mL to the 6 to make 15.0. Technically, you want the final volume to be 15.0 mL; the amount you add may NOT be EXACTLY 9.0 mL since volumes are not additive.