When 24.2 kg of Fe2O3 react with 14.5 kg of CO and 5.4 kg of Fe are recovered, what is the percent yield for the reaction?
mols Fe2O3 = grams/molar mass
mols CO = grams/molar mass
Convert mols Fe2O3 to mols Fe
Convert mols CO to mols Fe.
Probably the two answers will not the same and one of them must be wrong. The correct answer in limiting reagent problems is always the smaller value and the reagent producing that number is the limiting reagent.
Convert mols of the smaller number to grams. g = mols x molar mass. This is the theoretical yield.
%yield = (actual yield/theoretical yield)*100 = ?