Trig

posted by .

solve over the indicated interval expressed in degrees to 2 decimal places. sec(theta/2)=1.4275, 0<theta<360degrees

  • Trig -

    sec(A/2) = 1.4275
    cos(A/2) = 1/1.4275 = 0.70053
    A/2 = 45.53
    A = 91.06o

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Trig

    Solve the following interval 0<_ (less than or equal to)0(Theta)<2pi: 1. sin0(theta) + sin2 0(theta) = 0 2. 2cos^20 (theta) + cos0 (theta) -1 = 0
  2. trig

    Write each identity expression in terms of:1. cos theta= a. sin^2theta ---------- sec^2theta-1 2. tan theta= a. sec theta over sin theta minus sec theta over cosecant theta.
  3. Trigonometry

    I don't understand how I'm supposed set the problem up or what theta is... Use the given function value(s), and trigonometric identities (including the cofunction identities), to find the indicated trigonometric functions. sec theta …
  4. Trig

    How do I solve the following? sec 3 theta/2 = 2 on the interval 0<theta<2 pi?
  5. trig

    Perform the indicated operation and simplify tan^2(theta)-3sin(theta)tan(theta)sec(theta)
  6. Trig

    Given 2secant^2 (theta) + 1 = 5 secant (theta), solve for (theta), to the nearest degree, in the interval 0 degrees is greater than or equal to (theta) which is less than 360 degrees
  7. trig

    If sin theta is equal to 5/13 and theta is an angle in quadrant II find the value of cos theta, sec theta, tan theta, csc theta, cot theta.
  8. tri

    solve exactly over the indicated interval: 2cos^2(theta)=cos(theta), 0<theta<2pi
  9. Precalculus

    Solve the equation for the indicated domain. sec(theta+81 degrees)=2 Theta E[0,360)
  10. Math (Right Triangle Trig)

    Suppose tan(theta)=5/7 and theta belongs to Quadrant III, find the exact value of sec(theta)?

More Similar Questions