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Every time Jim shoots a free throw in basketball, he has an 80% chance of making the shot. He is given 3 free throws. Find the probability of each event.

a) misses all 3 shots
b) misses the first two shots and makes the third.

Can someone please explain to me how to get the answer? Thank you

  • Math -

    They are independent events. Multiply the probabilities
    prob making=.8 probab missin=.2

    a. mass all three: .2*.2*.2
    misstwo, make last: .2*.2*.8

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