calculus (gr 12)
posted by HELP MEE .
Determine the velocity and acceleration as functions of time, t, for s(t) = 45t − 5t^2, where
s(t) represents the distance as a function of time. (Hint: velocity and acceleration correspond to the first and
second derivatives of the distance)
calculus (gr 12) -
v = 45 - 10t
a = -10