# calculus (gr 12)

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Determine the velocity and acceleration as functions of time, t, for s(t) = 45t − 5t^2, where
s(t) represents the distance as a function of time. (Hint: velocity and acceleration correspond to the first and
second derivatives of the distance)

• calculus (gr 12) -

v = 45 - 10t
a = -10

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