3PbO + 2NH3 ---> 3Pb + N2 + 3H2O
Based on the above balanced equation, If given 12.6 moles of NH3, how many moles of lead (Pb) will be produced
To find the number of moles of lead (Pb) produced, we need to use the coefficients of NH3 and Pb from the balanced equation.
According to the equation: 3PbO + 2NH3 ---> 3Pb + N2 + 3H2O
The coefficient of NH3 is 2, and the coefficient of Pb is 3. This means that for every 2 moles of NH3, 3 moles of Pb are produced.
Given that we have 12.6 moles of NH3, we can set up a simple ratio to determine the number of moles of Pb produced.
(12.6 moles NH3) x (3 moles Pb / 2 moles NH3) = 18.9 moles Pb
Therefore, if we have 12.6 moles of NH3, we would produce 18.9 moles of lead (Pb) based on the balanced equation.