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What mass of precipitate will form if 1.50L of concentrated Pb(ClO3)2 is mixed with 0.200L of 0.280M of NaI? Assume the reaction is complete

  • Chemistry -

    You must assume there is enough Pb(ClO3)2 to use all of the NaI.
    Pb(ClO3)2 + 2NaI ==> PbI2 + 2NaClO3
    mols NaI = M x L = ?
    Convert mols NaI to mols PbI2 using the coefficients in the balanced equation.
    Convert mols PbI2 to g. g = mols x molar mass.

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