A bomber takes off and flies at 500kph. A fighter, setting out 2 1/2 hrs later flies at 750kph. How long will it take for the fighter to catch the bomber, and how far will the bomber have travelled at this time?
d1 = 500*t
d2 = 750*(t-2.5).
d1 = d2 After fighter catches bomber.
500t = 750(t-2.5)
500t = 750t-1875
750t-500t = 1875
250t = 1875
t = 7.5 h.
a. t-2.5 = 5 h. to catch the bomber.
b. d = 500*t = 500*7.5 = 3750 km