barium chloride+ alumium sulphate »barium sulphate + allumium chloride (balance the equation step by step)
To balance the chemical equation "barium chloride + aluminum sulfate → barium sulfate + aluminum chloride", follow these step-by-step instructions:
Step 1: Write down the unbalanced equation.
BaCl₂ + Al₂(SO₄)₃ → BaSO₄ + AlCl₃
Step 2: Count the number of atoms for each element on both sides of the equation.
On the left side: 1 Ba, 2 Cl, 2 Al, 3 S, and 12 O
On the right side: 1 Ba, 1 S, 4 O, and 3 Cl
Step 3: Balance elements that appear in only one compound first. In this equation, it's Barium (Ba).
Since there is one Ba on both sides, it is already balanced.
Step 4: Balance elements that appear in more than one compound. Start with Chlorine (Cl).
Counting Cl atoms, we have 2 on the left side and 3 on the right side.
To balance Cl, we need to put a 3 in front of AlCl₃, giving us:
BaCl₂ + Al₂(SO₄)₃ → BaSO₄ + 3 AlCl₃
Step 5: Next, balance the Sulfur (S) atoms.
Counting S atoms, we have 3 on the left side and 1 on the right side.
To balance S, we need to put a 3 in front of BaSO₄, giving us:
BaCl₂ + Al₂(SO₄)₃ → 3 BaSO₄ + 3 AlCl₃
Step 6: Finally, balance the Aluminum (Al) atoms.
Counting Al atoms, we have 2 on the left side and 3 on the right side.
To balance Al, we need to put a 2 in front of AlCl₃, giving us the final balanced equation:
BaCl₂ + Al₂(SO₄)₃ → 3 BaSO₄ + 2 AlCl₃
The balanced equation is: BaCl₂ + Al₂(SO₄)₃ → 3 BaSO₄ + 2 AlCl₃