Vector A is described as having magnitude -7 and angle 30degress. Which is an equivaent statement of magnitude and angle of vector A? (Note: All angles are measured counterclockwise from x-axis.)
A = -7[30o] = -7*cos30 + i(-7)*sin30
A = -6.06 - 3.5i. Q3.
tanB = Y/X = -3.5/-6.06 = 0.57756
Br = 30o = Reference angle.
B = 30 + 180 = 210o.A =
A = -6.06/cos210 = 7[210o].
To find an equivalent statement of the magnitude and angle of vector A, we need to convert the given information into a different form.
Let's start with the magnitude. The magnitude of a vector is always a positive value, so we need to take the magnitude of -7 and make it positive. Therefore, the equivalent magnitude is 7.
Now, let's consider the angle. The given angle is 30 degrees counterclockwise from the x-axis. To find an equivalent statement, we can add or subtract multiples of 360 degrees to this angle because adding or subtracting complete revolutions does not change the end result.
Let's add 360 degrees to the given angle:
30 degrees + 360 degrees = 390 degrees
Therefore, an equivalent statement of the magnitude and angle of vector A is a magnitude of 7 and an angle of 390 degrees.