calculus
posted by Liz .
Find the length of the curve over the given interval:
x=t+1
y=ln cos(t)
for t=0 > t=pi/4
Respond to this Question
Similar Questions

calculus
g(t)=2+cos t; [0,pi] Can you help me find the average rate of change of the function over the given interval? 
Calculus
Find the definite integral that represents the arc length of the curve y=sqrt(x) over the interval [0, 3] 
Parametric Equations
Find the length of the curve over the given interval: x=t+1 y=ln cos(t) for t=0 > t=pi/4 
Parametric Equations
Find the length of the curve over the given interval: x=t+1 y=ln cos(t) for t=0 > t=pi/4 
calculus
Find the length of the curve over the given interval: x=t+1 y=ln cos(t) for t=0 > t=pi/4 
Calculus
Find the arc length of the curve described by the parametric equation over the given interval: x=t^(2) + 1 y=2t  3 > 0<t<1 
Calculus
Find the arc length of the curve described by the parametric equation over the given interval: x=t^(2) + 1 y=2t  3 0<t<1 
Calculus
Consider the curve below. x = (cos(t))^2 y = cos(t) 0 ≤ t ≤ 6π (a) Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. (b) What is the length of the curve? 
Calculus
Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = cos^2 t, y = cos t, 0 ≤ t ≤ 9π and the length of the curve so far i got ∫0 to 9pi √((2cos(t)sin(t))^2+(sint)^2) I … 
calculus
Find the length of the curve given by the equation y= intergral from pi to x of sqrt(cos(t)) dt for x between pi and pi. I think I know to do this at least part of it. I am using the fundamental theorem of calculus and the arc length …