1) a car moving at 50km/h crashes Into the barrier and stops in 0.25 m a) if a 10kg child were to be stopped in the same time , what is the average force must be exerted ? c)approximately what is the mass of an object whose weight equals to the force in Part b?Could you lift such a mass with your arms ? d) what does your answer to part c say about holding an infant on your lap instead of using a separate infant restraint? PS : I know answer abc but am stuck with d! A) t: 0.036s b) delta P : 139kg.m/s2 F: -3858N c) m : 393.7 no we can't ! D) ????? 2 ) If you jump off a table as your feet hit the floor let your legs bend at the knees explain why.5) a) 35g bullet Strikes at 5 kg stationary wooden block and embeds itself in the block the block and the Bullet fly out together at 8.6 m/s what was the original velocity of the bullet? 6) a 0.50kg ball traveling at 6m/s collides head on with a 1kg ball moving in the opposite direction at a velocity of -12m/s . The 0.50 ball Moves away at -14.0 m/s up aftet the collosion find the velocity of the second ball. Please THERE IS A LOT OF QUETIONS BUT THESE ARE THE ONES I DON'T GET!HELP

Try posting your questions one at a time. Question 1 has no part b.

1) a) To find the average force exerted on the 10kg child, we can use Newton's second law of motion, which states that force is equal to mass times acceleration. In this case, the acceleration can be calculated using the formula v = u + at, where v is the final velocity (0 m/s), u is the initial velocity (unknown in this case), a is the acceleration, and t is the time taken to stop.

Given that the time taken to stop is 0.25 s, we can rearrange the formula to solve for acceleration: a = (v - u) / t.

Plugging in the values, we have 0 = (u - 0) / 0.25. Solving for u, we get u = 0.

Since the initial velocity of the child is 0 m/s, the average force exerted on the child can be found by multiplying the mass (10 kg) by the acceleration (0 m/s^2), giving us an average force of 0 Newtons.

b) The change in momentum (ΔP) can be calculated using the formula ΔP = m * Δv, where m is the mass and Δv is the change in velocity.

In this case, the mass is unknown, so we can rearrange the formula to solve for mass: m = ΔP / Δv.

Given that the change in momentum (ΔP) is 139 kg.m/s^2 and the change in velocity (Δv) is 8.6 m/s, we can calculate the mass: m = 139 / 8.6 = 16.16 kg.

c) The weight of an object can be calculated using the formula weight = mass * gravity, where mass is the mass of the object and gravity is the acceleration due to gravity (approximately 9.8 m/s^2 on Earth).

In this case, the force from part b is equal to the weight of the object, so we can use the same formula to find the mass of the object: m = F / g = 3858 / 9.8 = 393.7 kg.

As for whether we can lift such a mass with our arms, it depends on the individual's strength. Some people may be able to lift this mass, while others may not.

d) Holding an infant on your lap instead of using a separate infant restraint is not safe. The force exerted on the infant during a crash could potentially be very high, as shown in part b. This force could result in serious injury to the child, which is why separate infant restraints, such as car seats, are recommended to provide proper protection.