Solve the system by addition or substitution. 3x – 4y = 8 6x – 2y = 10 Please get me on the correct track for 3x -4y =8 x=4, y=1 for 6x - 2y =10 x= 2, y= 1 Solve one equation for x. 3x = 4y + 8 x = (4y + 8)/3 Insert that value …
1. Solve for x. 4(x - b) = x b = 4/3x b = 3/4x x = 4/3b x = 3/4b 2. Solve for y, then find the value of y when given x = 2. 6x = 7 - 4y -12 7/4 19/4 24 I need help solving these. Can you please explain how to solve these problems?
How do I solve these inequalities: e^3x>e^x-1 -6log (subscript of 4) x > -24 & how do I solve these: 8^x+1=3 e^x+2=50 8logx=16 I really don't understand how to solve these so can someone please explain them to me?
Assume that x,y and a are positive numbers. Use the properties of logarithms to write the following expression - log a x^6 y^7 a. 42log a x+y b. 42log a x+7log a y c. 6log a x+42log a y d. 6log a x+7log a y e. 6log a x+6log a y